In a pickup game of dorm shuffleboard,students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.

Question

In a pickup game of dorm shuffleboard,students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.90 m by the horizontal 25 N force from the broom and then has a speed of 1.60 m/s,what is the coefficient of kinetic friction between the book and floor?

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Helga 4 months 2021-09-04T11:06:24+00:00 1 Answers 5 views 0

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    2021-09-04T11:07:50+00:00

    Answer:

    Coefficient of friction between the book and floor is 0.582.

    Explanation:

    Using the velocity formula;

    v^2 = 2as

    a = v^2/(2s)

    a = 1.6^2/(2*0.9)

    a = 2.56/1.8

    a = 1.42 m/s^2

    the force necessary to give the book the acceleration is  

    F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)

    F = 4.98 N

    The difference in the force is the friction force, which is

    Ff = 25 – 4.98 = 20 N

    Ff = mgμ

    where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2

    μ = Ff/mg

    μ = 20/(3.5*9.81)

    μ = 0.582

    Coefficient of friction between the book and floor is 0.582.

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