In a Millikan oil-drop experiment (Section 22-8), a uniform electric field of 5.78 x 105 N/C is maintained in the region between two plates

Question

In a Millikan oil-drop experiment (Section 22-8), a uniform electric field of 5.78 x 105 N/C is maintained in the region between two plates separated by 8.56 cm. Find the potential difference (in V) between the plates.

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Helga 3 years 2021-08-30T23:48:37+00:00 1 Answers 13 views 0

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    2021-08-30T23:49:57+00:00

    Answer:

    The required potential difference is 4.95 \times 10^{4}~V.

    Explanation:

    We know, electric field is nothing but the negative gradiant of potential. Mathematically, in three-dimension,

    \vec{E} = -\vec{\nabla}V

    In one dimension, the magnitude of the electric field is

    E = \dfrac{V}{x}

    where ‘V‘ is the applied voltage and ‘x‘is the distance through which the voltage is applied.

    Given, V = 5.78 \times 10^{5}~N~C^{-1}~ and~ x = 8.56~cm = 0.0856~m.

    So the required potential difference is

    V = E \times x = 5.78 \times 10^{5}~N~C^{-1} \times 0.0856~m = 4.95 \times 10^{4}~V

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