In a hydraulic lift, if you exert a downward force of 100 N on a piston with an area of 1 m^3, how much upward force would be exerted on a p

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In a hydraulic lift, if you exert a downward force of 100 N on a piston with an area of 1 m^3, how much upward force would be exerted on a piston with an area of 20 m^3?

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Diễm Kiều 2 months 2021-07-23T17:29:43+00:00 1 Answers 0 views 0

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    2021-07-23T17:31:42+00:00

    Answer:

    F_2=2000\ N          

    Explanation:

    We have,

    Area 1, A_1=1\ m^3

    Force 1, F_1=100\ N

    Area 2, A_2=20\ m^3

    It is required to find the force 2. In a hydraulic lift, the pressure at two points is same. It means :

    P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}

    F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{100\times 20}{1}\\\\F_2=2000\ N

    So, second force is 2000 N.

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