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## In a double slit interference experiment, the distance between the slits is 0.0005m and the screen is 2 meters from the slits. Yellow light

Question

In a double slit interference experiment, the distance between the slits is 0.0005m and the screen is 2 meters from the slits. Yellow light from a sodium lamp is used and it has a wavelength of 5.89 x 10-7 m. What is the distance between the first and second bright fringes on the screen?

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Physics
6 months
2021-07-20T03:06:00+00:00
2021-07-20T03:06:00+00:00 1 Answers
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## Answers ( )

Answer:4.712 mm or 0.004712 m

Explanation:Parameters given:

Distance between the slits, d = 0.0005 m

Distance between the screen and the slits, R = 2 m

Wavelength of the light, λ =

The

condition for the maxima in a double slit experimentis given as:mλ =

where Y = distance between the first order maxima and the

mth order maximaIn this case, m = 2.

Therefore:

Y = mλR/d

Y =

Y = 0.004712 m = 4.712 mm

The

distance between the first and second bright fringes is 4.712 mm.