In a double-slit experiment using light of wavelength 486 nm, the slit spacing is 0.600 mm and the screen is 2.00 m from the slits. Find the

Question

In a double-slit experiment using light of wavelength 486 nm, the slit spacing is 0.600 mm and the screen is 2.00 m from the slits. Find the distance along the screen between adjacent bright fringes.

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bonexptip 5 months 2021-08-09T15:54:11+00:00 1 Answers 32 views 0

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    2021-08-09T15:55:31+00:00

    Answer:

    The distance is y =  0.00162 \ m

    Explanation:

    From the question we are told that

        The wavelength is  \lambda  =  486 \ nm  =  486 *10^{-9} \ m

       The  slit spacing is  d =  0.600 \ mm   =  0.60 *10^{-3} \ m

        The distance of the screen is  D = 2.0 \ m

     Generally the distance along the screen between adjacent bright fringes is mathematically represented as  

            y =  \frac{\lambda  * D}{d}

    substituting values

             y =  \frac{ 486 *10^{-9}  * 2}{0.6*10^{-3}}

             y =  0.00162 \ m

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