In a certain lottery, five different numbers between 1 and 35 inclusive are drawn. These are the winning numbers. To win the lottery, a pers

Question

In a certain lottery, five different numbers between 1 and 35 inclusive are drawn. These are the winning numbers. To win the lottery, a person must select the correct 5 numbers in the same order in which they were drawn. What is the probability of winning

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Trúc Chi 2 months 2021-07-22T08:56:55+00:00 1 Answers 3 views 0

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    2021-07-22T08:58:18+00:00

    Answer:

    Pr =\frac{1}{38955840}

    Step-by-step explanation:

    Given

    n = 35 —- 1 to 35

    r = 5 — selection

    Required

    The probability of winning

    The probability of getting the first number correctly is:

    P(1) = \frac{1}{35}

    At this point, the remaining numbers are 34

    So, the second selection has the following probability

    P(2) = \frac{1}{34}

    Following the above sequence, we have:

    P(3) = \frac{1}{33}

    P(4) = \frac{1}{32}

    P(5) = \frac{1}{31}

    So, the required probability is:

    Pr =P(1) * P(2) * P(3) * P(4) * P(5)

    Pr =\frac{1}{35} *\frac{1}{34}*\frac{1}{33}*\frac{1}{32}*\frac{1}{31}

    Pr =\frac{1}{35*34*33*32*31}

    Pr =\frac{1}{38955840}

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