In a certain country, the true probability of a baby being a boy is 0.519. Among the next nine randomly selected births in the country

Question

In a certain country, the true probability of a baby being a boy is 0.519. Among the next nine randomly selected births
in the country, what is the probability that at least one of them is a girl?

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Calantha 18 hours 2021-07-22T19:53:22+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-22T19:54:57+00:00

    Answer:

    0.9973

    Step-by-step explanation:

    Given :

    Probability of girl, probability of success , 1 – p = 1 – 0.519 = 0.481

    1 – p = 0.481

    n = 9

    Probability that atleast one is girl

    Usingbthe binomial probability distribution :

    P(x =x) = nCx * p^x * (1 – p)^(n – x)

    USing the binomial probability calculator :

    p(x ≥ 1) = p(x=1) + p(x=2) + p(x=3) + p(x=4) + p(x=5) + p(x=6) + p(x=7) + p(x=8) + p(x=9)

    p(x ≥ 1) = 0.9973 ( from calculator).

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