Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1

Question

Imagine that an electron in an excited state in a nitrogen molecule decays to its ground state, emitting a photon with a frequency of 8.88×1014 Hz . What is the change in energy, ΔE, that the electron undergoes to decay to its ground state?

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Euphemia 4 years 2021-08-28T10:29:28+00:00 1 Answers 150 views 0

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  1. thaiduong
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    2021-08-28T10:30:37+00:00
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    Answer: 5.884×10^-19 J

    Explanation:

    The change in energy will be the product of the planck constant and the frequency of radiation.

    ΔE = hf

    Where h = planck constant = 6.626×10^-34 m²kg/s

    f = 8.88×10^14 Hz

    ΔE = 6.626×10^-34 × 8.88×10^14 = 58.84×10^-20 = 5.884×10^-19 J

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