## If you wish to take a picture of a bullet traveling at 530 m/s, then a very brief flash of light produced by an RC discharge through a flash

Question

If you wish to take a picture of a bullet traveling at 530 m/s, then a very brief flash of light produced by an RC discharge through a flash tube can limit blurring. Assuming 1.00 mm of motion during one RC constant is acceptable, and given that the flash is driven by a 530 µF capacitor, what is the resistance (in Ω) in the flash tube?

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Physics
4 days
2021-07-18T23:20:44+00:00
2021-07-18T23:20:44+00:00 1 Answers
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## Answers ( )

Answer: 3.56*10^-3 Ω

Explanation:

Given

Speed of bullet, v = 530 m/s

Distance during one RC time constant, d = 1 mm = 1*10^-3 m

Capacitance of the capacitor, C = 530 µF

v = d / t = d / τ, so that

τ = d / v

The time constant for the RC circuit is

τ = RC, if we make R subject of formula we have

R = τ / C. Substituting the relation for τ

R = d / vC

R = 1*10^-3 / (530 * 530*10^-6)

R = 1*10^-3 / 0.2809

R = 3.56*10^-3 Ω

Therefore, the resistance in the flash tube is 3.56*10^-3 mΩ