If you wish to take a picture of a bullet traveling at 530 m/s, then a very brief flash of light produced by an RC discharge through a flash

Question

If you wish to take a picture of a bullet traveling at 530 m/s, then a very brief flash of light produced by an RC discharge through a flash tube can limit blurring. Assuming 1.00 mm of motion during one RC constant is acceptable, and given that the flash is driven by a 530 µF capacitor, what is the resistance (in Ω) in the flash tube?

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Thái Dương 4 days 2021-07-18T23:20:44+00:00 1 Answers 2 views 0

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    2021-07-18T23:22:28+00:00

    Answer: 3.56*10^-3 Ω

    Explanation:

    Given

    Speed of bullet, v = 530 m/s

    Distance during one RC time constant, d = 1 mm = 1*10^-3 m

    Capacitance of the capacitor, C = 530 µF

    v = d / t = d / τ, so that

    τ = d / v

    The time constant for the RC circuit is

    τ = RC, if we make R subject of formula we have

    R = τ / C. Substituting the relation for τ

    R = d / vC

    R = 1*10^-3 / (530 * 530*10^-6)

    R = 1*10^-3 / 0.2809

    R = 3.56*10^-3 Ω

    Therefore, the resistance in the flash tube is 3.56*10^-3 mΩ

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