If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge through a flash

Question

If you wish to take a picture of a bullet traveling at 500 m/s, then a very brief flash of light produced by an RC discharge through a flash tube can limit blurring. Assuming 1.00 mm of motion during one RC constant is acceptable, and given that the flash is driven by a 600-μF capacitor, what is the resistance in the flash tube?

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Thiên Thanh 2 weeks 2021-09-04T11:24:17+00:00 1 Answers 0 views 0

Answers ( )

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    2021-09-04T11:25:40+00:00

    Explanation:

    The given data is as follows.

           Speed of the bullet (v) = 500 m/s

         Distance during one RC time constant (d) = 1 mm = 1 \times 10^{-3} m

          Capacitance (C) = 600 \mu F = 600 \times 10^{-6} F

    Hence, formula for speed of the bullet is as follows.

                    v = \frac{d}{t}

    or,           t = \frac{d}{v}

    Time constant for RC circuit is as follows.

              t = RC

            R = \frac{t}{C}

                = \frac{d}{vC}

                = \frac{1 \times 10^{-3}}{500 \times 600 \times 10^{-6}}

                = 3.33 \times 10^{-3} ohm

    Thus, we can conclude that resistance in the flash tube is 3.33 \times 10^{-3} ohm.

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