If you ran the reaction for this experiment and began with 65.0 mmol of isopentyl alcohol, how many grams of isopentyl acetate could you the

Question

If you ran the reaction for this experiment and began with 65.0 mmol of isopentyl alcohol, how many grams of isopentyl acetate could you theoretically produce assuming only a 77.0% attainable yield

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Nho 6 months 2021-07-12T11:31:13+00:00 1 Answers 1 views 0

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    2021-07-12T11:33:00+00:00

    Answer:

    6.52g = Actual yield (g)

    Explanation:

    The yield of a reaction is:

    Percent yield = Actual yield (g) / Theoretical Yield (g) * 100

    As 1 mol of isopentyl alcohol produce 1 mol of isopentyl acetate (Theoretical Yield), the theroretical yield of isopentyl acetate is 65.0mmol = 0.0650mol. To solve this question we need to convert the moles of isopentyl acetate to mass using its molar mass (130.19g/mol).

    With the equation of percent yield we can find the mass obtained as follows:

    Theoretical yield:

    0.0650mol * (130.19g/mol) = 8.46g of isopentyl alcohol

    Mass produced:

    77 = Actual yield (g) / 8.462g * 100

    6.52g = Actual yield (g)

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