If you have a line that goes through (-1, 7) and (8, -2), what would the equation of the line be in point-slope form? Please us

Question

If you have a line that goes through (-1, 7) and (8, -2), what would the equation of the line be in point-slope form?

Please use (8, -2) for x1 and y1.

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Lệ Thu 6 months 2021-07-21T15:50:08+00:00 1 Answers 3 views 0

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    2021-07-21T15:51:20+00:00

    Answer:


    y-9 = -1/12(x-8)

    Step-by-step explanation:


    To write an equation of a line perpendicular to the graph of y = 12x-3 and passing through the point, we will follow the following steps.


    The standard form of point-slope form of the equation of a line is  given as


    y − y1 = m(x − x1),


    m is the slope of the unknown line


    (x1, y1) is a point on the line.


    Step 1: We need to calculate the slope of the known line first,


    Given y = 12x-3


    from the equation, m = 12 on comparison.


    Step 2: get the slope of the unknown line. since the line given is perpendicular to the line y = 12x – 3, the product of their slope will be -1 i.e Mm = -1


    M = -1/m


    M is the slope of the unknown line


    M = -1/12


    Step 3: We will substitute M = -1/12 and the point (8, 9) into the point-slope form of the equation of a line i.e y − y1 = M(x − x1),


    M = -1/12, x1 = 8 and y1 = 9


    y-9 = -1/12(x-8)


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