If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O? CO2

Question

If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O?
CO2
H2O
C3H6
O2

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Kiệt Gia 4 years 2021-08-13T03:51:56+00:00 1 Answers 7 views 0

Answers ( )

  1. Sapo1
    0
    2021-08-13T03:53:02+00:00
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    Answer:

    The limiting reactant is propene, C_3H_6.

    Explanation:

    2C_3H_6 + 9O_2 \rightarrow 6CO_2 + 6H_2O

    Moles of nitrogen propene  = 2 mol

    Moles of oxygen  = 10 mol

    According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:

    =\frac{9}{2}\times 2mol=9\text{mol of oxygen gas}

    According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.

    The limiting reactant is propene, hence the correct answer is the C_3H_6.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )