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IF YOU ANSERW MY MATH QUESTIONS ILL GIVE ADTINAL 50) POINTS FOR each question and crown evry question. A scientist uses a submarine to
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IF YOU ANSERW MY MATH QUESTIONS ILL GIVE ADTINAL 50) POINTS FOR each question and crown evry question.
A scientist uses a submarine to study ocean life.
*She begins at sea level, which is an elevation of 0 feet.
*She descends for 91 seconds at a speed of 2.2 feet per second.
*She then ascends for 32 seconds at a speed of 0.7 feet per second.
At this point, what is her elevation, in feet?
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2021-09-05T01:16:08+00:00
2021-09-05T01:16:08+00:00 2 Answers
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Answer:
220.4 feet below sea level
Step-by-step explanation:
use the following formula:
rate x time = distance
(rate going down)(time going down) = distance going down.
so if she starts at 0 feet above sea level, and descends for 91 seconds at a speed of 2.2 ft/sec. you would plug that in as:
(2.2 ft/sec)(91 seconds) = distance of 198 feet.
she then ascends for 32 seconds at a speed of 0.7 feet/second.
so, substitute that;
(0.7 ft/sec)(32sec) = distance of 22.4 feet.
distance traveled downward + distance traveled upward = total distance of location.
198 + 22.4 feet = 220.4 feet
Answer:
-177.8 feet below sea level.
Step-by-step explanation:
First, we know that descend means to lower. Anything lower than 0 has to be negative. It says that she descends for 91 seconds at a speed of 2.2 feet per second. So first to find out how many feet she descended in those 91 seconds, you need to multiply 91*-2.2= -200.2. Then, it says that she ascends for 32 seconds at the speed of 0.7 feet per second. It’s the same thing, but ascend means to go up. So, we multiply 32*0.7=22.4. Now we add the two numbers together to get -177.8.