If vector A has components Ax and Ay and makes an angle θ with the +x axis, thena. Ax +Ay (where A is magnitude of A)b. θ= Ay/Axc. Cosθ=

Question

If vector A has components Ax and Ay and makes an angle θ with the +x axis, thena. Ax +Ay (where A is magnitude of A)b. θ= Ay/Axc. Cosθ= Ax/ √ (Ax^2+ Ay^2)d. Tanθ= Ax/Ay

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Verity 2 months 2021-07-25T05:26:07+00:00 1 Answers 2 views 0

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    2021-07-25T05:27:57+00:00

    Answer:

    c.  Cos θ =  A_{x} / \sqrt{(A_{x} ^{2} + A_{y} ^{2}) }

    Explanation:

    A vector is any quantity that has both magnitude and direction. The given vector A has components A_{x} and A_{y}, and makes angle  θ with +x axis.

    Thus;

    Resultant of the vector, A = \sqrt{(A_{x} ^{2} + A_{y} ^{2}) }

    Therefore, the components, angle and resultant of vector A can be represented in magnitude and direction by the three sides of a right angled triangle.

    Applying the appropriate trigonometric function to the triangle for vector A, we have;

    Cos θ =  A_{x} ÷   \sqrt{(A_{x} ^{2} + A_{y} ^{2}) }

    ⇒   Cos θ =  A_{x} / \sqrt{(A_{x} ^{2} + A_{y} ^{2}) }

    The correct option is C.

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