If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen distance to be 40

Question

If u shine a light of frequency 375Hz on a double slit setup, and u measure the slit separation to be 950nm and the screen distance to be 4030 nm away what is the distance from the zero order fringe to the first order fringe

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niczorrrr 4 years 2021-07-30T16:38:15+00:00 1 Answers 10 views 0

Answers ( )

  1. Latifah
    0
    2021-07-30T16:40:07+00:00
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    Answer:

    Y = 3.39 x 10⁶ m

    Explanation:

    We will use Young’s Double Slit formula here:

    Y = \frac{\lambda L}{d}

    where,

    Y = Fringe spacing = ?

    λ = wavelength = \frac{speed\ of\ light}{frequency} = \frac{3\ x\ 10^8\ m/s}{375\ Hz} = 8 x 10⁵ m

    L = screend distance = 4030 nm = 4.03 x 10⁻⁶ m

    d = slit separation = 950 nm = 9.5 x 10⁻⁷ m

    Therefore,

    Y = \frac{(8\ x\ 10^5\ m)(4.03\ x\ 10^{-6}\ m)}{9.5\ x\ 10^{-7}\ m}

    Y = 3.39 x 10⁶ m

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