If there are 3.0 liters of gas at a pressure of 2.0 atm at constant temperature, what is the pressure if the volume is reduced by one half?

Question

If there are 3.0 liters of gas at a pressure of 2.0 atm at constant temperature, what is the pressure if the volume is reduced by one half?

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Thu Hương 4 years 2021-08-22T11:00:52+00:00 1 Answers 17 views 0

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  1. phucdien
    0
    2021-08-22T11:02:46+00:00
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    Answer:

    The pressure is doubled, 4.0atm

    Explanation:

    Based on Boyle’s law, the pressure of a gas is inversely proportional to its volume at constant temperature. The equation that describes this law is:

    P1V1 = P2V2

    Where P is pressure and V volume at 1, initial state and 2, final state of the gas.

    Computing the values of the problem:

    P1 = 2.0atm

    V1 = 3.0L

    P2 = ?

    V2 = 3.0L / 2 = 1.5L

    Replacing:

    2.0atm*3.0L = P2*1.5L

    6.0atmL / 1.5L = P2

    4.0atm = P2

    The pressure is doubled, 4.0atm

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )