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If the work required to speed up a car from 11 km/h to 21 km/h is 6.0×103 J , what would be the work required to increase the car’s speed fr
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Explanation:
We need convert the velocities first to m/s and we get the following:
v2 = 21 km/hr = 5.8 m/s
v1 = 11 km/hr = 3.1 m/s
We need to find the mass of the car also for later use do using the work-energy theorem:
[tex]delta \: w = \frac{1}{2} m(v \frac{2}{2} – v\frac{2}{1} )[/tex]
6.0×10^3 J = (0.5) m [(5.8)^2 – (3.1)^2]
or
m = 499.4 kg
Now we determine work needed delta W to change its velocity from 21 km/hr to 33 km/hr
v2 = 33 km/hr = 9.2 m/s
v1 = 21 km/hr = 5.8 m/s
delta W = (0.5)(499.4)[(9.2)^2 – (5.8)^2]
= 1.3 x 10^4 J