If the space station is 190 m in diameter, what angular velocity would produce an “artificial gravity” of 9.80 m/s2 at the rim? Give your an

Question

If the space station is 190 m in diameter, what angular velocity would produce an “artificial gravity” of 9.80 m/s2 at the rim? Give your answer in rad/s.

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Neala 1 year 2021-09-05T00:58:09+00:00 1 Answers 20 views 0

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    2021-09-05T00:59:41+00:00

    Answer:

    The angular velocity produced is 0.321 rad/s.

    Explanation:

    Given :

    Diameter of space station , D = 190 m.

    Therefore, radius , [tex]R=\dfrac{D}{2}=\dfrac{190}{2}=95\ m.[/tex]

    Also, acceleration , [tex]a=9.8\ m/s^2.[/tex]

    We know, angular velocity , [tex]\omega=\sqrt \dfrac{a}{R}[/tex].

    Putting value of g and R in above equation.

    We get ,

    [tex]\omega=\sqrt \dfrac{9.8\ m/s^2}{95\ m}[/tex]

    [tex]\omega=0.321\ rad/s.[/tex]

    Hence, this is the required solution.

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