if the rotation of a planet of radius 7.66 x 10^6 m and free-fall acceleration 8.34 m/s^2 increased to the point that the centripetal accele

Question

if the rotation of a planet of radius 7.66 x 10^6 m and free-fall acceleration 8.34 m/s^2 increased to the point that the centripetal acceleration was equal to the gravitational acceleration at the equator, what would be the tangential speed of a person standing at the equator?
answer in units of m/s​​

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Tryphena 1 year 2021-07-20T21:56:20+00:00 1 Answers 7 views 0

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    2021-07-20T21:57:24+00:00

    Answer:

    On the surface of the moon the weight of an object points towards the center of the moon and its magnitude is approximately 1/6 the magnitude of its weight on the surface of the earth. The mass of the object, i.e. its resistance to acceleration, is the same everywhere

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