if the product of two consecutive even number is 224 find the number July 28, 2021 by Thành Công if the product of two consecutive even number is 224 find the number
Let the first consecutive even number be x. The second one is going to be two more than x, and as such can be written as (x+2). The product of these numbers, x and (x+2), is 224: x(x+2)=224 x²+2x=224 x²+2x-224=0 (x+16)(x-14) =0 (could also use ‘-b’ method) x=-16 or 14 Therefore, (x+2) = -14 or 16 Therefore, the numbers are either 14 and 16, or -14 and -16 Reply
Answer: Let one integer be x, and the other be (x+2) x(x+2)=224 x2+2x-224=0 (x+16)(x-14) =0 x=-16 or 14 so x+2 = -14 or 16 So the integers are either 14 and 16 or -14 and -16. Step-by-step explanation: was that the question? Reply
Let the first consecutive even number be x. The second one is going to be two more than x, and as such can be written as (x+2).
The product of these numbers, x and (x+2), is 224:
x(x+2)=224
x²+2x=224
x²+2x-224=0
(x+16)(x-14) =0 (could also use ‘-b’ method)
x=-16 or 14
Therefore, (x+2) = -14 or 16
Therefore, the numbers are either 14 and 16, or -14 and -16
Answer:
Let one integer be x, and the other be (x+2)
x(x+2)=224
x2+2x-224=0
(x+16)(x-14) =0
x=-16 or 14
so x+2 = -14 or 16
So the integers are either 14 and 16 or -14 and -16.
Step-by-step explanation:
was that the question?