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If the pressure in a gas cylinder is heated to 354.2 K with the pressure of 2.64 atm that was the initial temperature if the initial pressur
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Answer:
Initial temperature of the gas cylinder was 167.7K
Explanation:
Based on Gay-Lussac’s law, the pressure of a gas under constant volume is directly proportional to its absolute temperature. The equation is:
P1*T2 = P2*T1
Where P is pressure and T absolute temperature of 1, initial state and 2, final state of the gas.
Replacing:
P1 = 1.25atm
T2 = 354.2K
P2 = 2.64atm
T1 = ?
1.25atm*354.2K = 2.64atm*T1
167.7K = T1
Initial temperature of the gas cylinder was 167.7K