Share
If the outermost electron in an atom is excited to a very high energy state, its orbit is far beyond that of the other electrons. To a good
Question
If the outermost electron in an atom is excited to a very high energy state, its orbit is far beyond that of the other electrons. To a good approximation, we can think of the electron as orbiting a compact core with a charge equal to the charge of a single proton. The outer electron in such a Rydberg atom thus has energy levels corresponding to those of hydrogen.
Sodium is a common element for such studies. How does the radius you calculated in part A compare to the approximately 0.20 nm radius of a typical sodium atom?
r100/rNa = _______.
in progress
0
Physics
6 months
2021-07-21T02:07:32+00:00
2021-07-21T02:07:32+00:00 1 Answers
12 views
0
Answers ( )
Answer:
the calculated ratio to the radius of the sodium
/
is 2645.0
Explanation:
Given the data in the question;
the calculated ratio to the radius of the sodium =
/ 
so from here we can write the number of energy states as 100
The number of energy states; n = 100
A;
We know that the radius of the sodium atom is;
Now, the value of the Bohr radius; α₀ = 5.29 × 10⁻¹¹ m
so lets determine the radius of the sodium atom; by substituting in our values;
B
given that, the theoretical value of the radius of the sodium is;
so we calculate the ratio of the radii of the sodium;
Therefore, the calculated ratio to the radius of the sodium
/
is 2645.0