If the electric field in an EM wave in free space has a peak magnitude of 8.1×10−5V/m, what is the peak magnitude of the magnetic field stre

Question

If the electric field in an EM wave in free space has a peak magnitude of 8.1×10−5V/m, what is the peak magnitude of the magnetic field strength? Express your answer using two significant figures.

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4 years 2021-08-27T23:49:28+00:00 1 Answers 16 views 0

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    2021-08-27T23:51:25+00:00

    Answer:

    2.7 * 10⁻¹³ T

    Explanation:

    The electromagnetic wave is produced when an oscillating electric and magnetic field interacts each other perpendicularly.

    In an electromagnetic wave, the electric field peak magnitude E and the magnetic field peak magnitude B are related by

    E = cB

    where ,

    c = 3 * 10⁸m/s

    E = 8.1×10−5V/m

    the peak magnitude of the magnetic field:

    B = \frac{E}{C} \\B = \frac{8.1 \times 10^-^5 }{3 \times 10^8 } \\= 2.7 \times 10^-^1^3

    2.7 * 10⁻¹³ T

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