If the distance from the center of a Ferris wheel to one of the seats is approximately 90 feet what is the distance traveled by a seated per

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If the distance from the center of a Ferris wheel to one of the seats is approximately 90 feet what is the distance traveled by a seated person, to the nearest foot, in four revolutions r=90 feet

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  1. Answer: 2261.9 ft

    Step-by-step explanation: One trip around is one circumference of a circle. The circumference is 2πr. That’s 2(π)(90 ft) = 565.4867 ft. Multiply by 4 trips around for a total distance of 2261.9 ft If you care about significant figures, then you only have report  sig fig, so that’s 2000 ft.

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