If the diameter of the low-power field is 1.5 mm, an object that occupies approximately a third of that field has an estimated diameter of

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If the diameter of the low-power field is 1.5 mm, an object that occupies approximately a third of that field has an estimated diameter of

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Thanh Hà 3 months 2021-08-01T13:31:22+00:00 1 Answers 4 views 0

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    2021-08-01T13:32:58+00:00

    Answer:

    d’ = 0.86 mm

    Explanation:

    First we need to find the area of low power field:

    A = πd²/4

    where,

    A = Area = ?

    d = diameter = 1.5 mm

    Therefore, using the value of diameter, we get:

    A = π(1.5 mm)²/4

    A = 1.767 mm²

    Now, the new object occupies 1/3rd of this area:

    A’ = (1/3)A

    πd’²/4 = (1/3)A

    d’² = (4/3π) A

    d’² = (4/3π)(1.767 mm²)

    d’ = √(0.75 mm²)

    d’ = 0.86 mm

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