If I have 4.4 moles of nitrous oxide (laughing gas) that is kept at 32.9 °C in a container under 1.6 atm, what is the volume of the containe

Question

If I have 4.4 moles of nitrous oxide (laughing gas) that is kept at 32.9 °C in a container under 1.6 atm, what is the volume of the container? (R = 0.0821 (L*atm)/(mol*K))

Round your answer to 1 decimal place.

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Thiên Di 2 months 2021-08-02T19:18:14+00:00 1 Answers 2 views 0

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    2021-08-02T19:20:12+00:00

    Answer:

    Explanation:

    Using the ideal gas equation as follows:

    PV = nRT

    Where:

    P = pressure (atm)

    V = volume (L)

    n = number of moles (mol)

    R = gas law constant (0.0821 Latm/molK)

    T = temperature (K)

    Based on the information provided in this question;

    P = 1.6atm

    n = 4.4 moles

    R = 0.0821 L*atm/mol*K

    T = 32.9°C = 32.9 + 273 = 305.9K

    V = ?

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