If hydrochloric acid is obtained commercially at a concentration of 12.1M, how many milliliters of 12.1M HCl(aq) must be used to prepare 2.0

Question

If hydrochloric acid is obtained commercially at a concentration of 12.1M, how many milliliters of 12.1M HCl(aq) must be used to prepare 2.00x103mL of 0.500M HCL(aq)?

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Sapo 2 months 2021-07-30T01:57:29+00:00 1 Answers 2 views 0

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    2021-07-30T01:58:29+00:00

    Answer:

    V_1=82.6mL

    Explanation:

    Hello there!

    In this case, according to this question, we will need to deal with this dilution problem, because it is asking for the volume of a 12.1-M stock solution of HCl. In such a way, we can use the following equation, under the assumption of no change in the number of moles in the solution:

    M_2V_2=M_1V_1

    Thus, we solve for the initial volume, V1, as shown below:

    V_1=\frac{M_2V_2}{M_1}

    And plug in the initial concentration and final concentration and volume to obtain:

    V_1=\frac{2000mL*0.500M}{12.1M}\\\\V_1=82.6mL

    Regards!

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