If f(1) =160 and f(n+1)=-2f(n), What is f(4)?

Question

If f(1) =160 and f(n+1)=-2f(n),
What is f(4)?

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Thiên Hương 2 months 2021-08-02T09:25:17+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-08-02T09:26:42+00:00

    Answer:

    f(n+1=-2f(n)

    f(x)=-2f(n)

    f(4)

    f(4)=-2f(4)

    0
    2021-08-02T09:26:44+00:00

    Answer:

    f(4) = – 1280

    Step-by-step explanation:

    Using the recursive rule and f(1) = 60 , then

    f(2) = – 2f(1) = – 2 × 160 = – 320

    f(3) = – 2f(2) = – 2 × – 320 = 640

    f(4) = – 2f(3) = – 2 × 640 = – 1280

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )