If an object is propelled upward from a height of 48 feet at an initial velocity of 96 feet per second, then its height after t seconds is g

Question

If an object is propelled upward from a height of 48 feet at an initial velocity of 96 feet per second, then its height after t seconds is given by the equation h(t)= -16t2+96t +48, where height is in feet. After how many seconds will the object reach a height of 192 feet?

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Kim Chi 3 years 2021-08-23T16:15:43+00:00 1 Answers 31 views 0

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    2021-08-23T16:17:12+00:00

    Answer:

    the number of seconds to reach the height is 3 seconds

    Step-by-step explanation:

    The computation of the seconds that reach the height is as follows;

    Given that

    h = -16t^2 + 96t + 48

    here

    H = 192 feet

    So,

    192 = -16t^2 + 96t + 48

    -16t^2 + 96t – 144 = 0

    Divide by -16

    t^2 – 6t + 9 = 0

    t^2 – 3t – 3t + 9

    t(t – 3) – 3(t – 3)

    t = 3 seconds

    Hence, the number of seconds to reach the height is 3 seconds

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )