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If an object is propelled upward from a height of 48 feet at an initial velocity of 96 feet per second, then its height after t seconds is g
Question
If an object is propelled upward from a height of 48 feet at an initial velocity of 96 feet per second, then its height after t seconds is given by the equation h(t)= -16t2+96t +48, where height is in feet. After how many seconds will the object reach a height of 192 feet?
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Mathematics
3 years
2021-08-23T16:15:43+00:00
2021-08-23T16:15:43+00:00 1 Answers
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Answers ( )
Answer:
the number of seconds to reach the height is 3 seconds
Step-by-step explanation:
The computation of the seconds that reach the height is as follows;
Given that
h = -16t^2 + 96t + 48
here
H = 192 feet
So,
192 = -16t^2 + 96t + 48
-16t^2 + 96t – 144 = 0
Divide by -16
t^2 – 6t + 9 = 0
t^2 – 3t – 3t + 9
t(t – 3) – 3(t – 3)
t = 3 seconds
Hence, the number of seconds to reach the height is 3 seconds