If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When

Question

If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When will the object hit the ground?

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1 year 2021-09-01T14:14:32+00:00 1 Answers 0 views 0

The object hits the ground after 3.52 seconds.

Step-by-step explanation:

The height of the object after t seconds is given by the following function:

$$h(t) = -16t^2 + 198$$

When will the object hit the ground?

It hits the ground when $$h(t) = 0$$. So

$$-16t^2 + 198 = 0$$

$$16t^2 = 198$$

$$t^2 = \frac{198}{16}$$

$$t^2 = 12.375$$

$$t = \pm \sqrt{12.375}$$

Since time is a positive measure, we only take the positive value

$$t = 3.52$$

The object hits the ground after 3.52 seconds.