If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When

Question

If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When will the object hit the ground?

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Kim Cúc 6 months 2021-09-01T14:14:32+00:00 1 Answers 0 views 0

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  1. huyenthanh
    0
    2021-09-01T14:15:43+00:00
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    Answer:

    The object hits the ground after 3.52 seconds.

    Step-by-step explanation:

    The height of the object after t seconds is given by the following function:

    h(t) = -16t^2 + 198

    When will the object hit the ground?

    It hits the ground when h(t) = 0. So

    -16t^2 + 198 = 0

    16t^2 = 198

    t^2 = \frac{198}{16}

    t^2 = 12.375

    t = \pm \sqrt{12.375}

    Since time is a positive measure, we only take the positive value

    t = 3.52

    The object hits the ground after 3.52 seconds.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )