If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When

Question

If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When will the object hit the ground?

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Kim Cúc 1 year 2021-09-01T14:14:32+00:00 1 Answers 0 views 0

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    2021-09-01T14:15:43+00:00

    Answer:

    The object hits the ground after 3.52 seconds.

    Step-by-step explanation:

    The height of the object after t seconds is given by the following function:

    [tex]h(t) = -16t^2 + 198[/tex]

    When will the object hit the ground?

    It hits the ground when [tex]h(t) = 0[/tex]. So

    [tex]-16t^2 + 198 = 0[/tex]

    [tex]16t^2 = 198[/tex]

    [tex]t^2 = \frac{198}{16}[/tex]

    [tex]t^2 = 12.375[/tex]

    [tex]t = \pm \sqrt{12.375}[/tex]

    Since time is a positive measure, we only take the positive value

    [tex]t = 3.52[/tex]

    The object hits the ground after 3.52 seconds.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )