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If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When
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If an object is dropped from a height of 198 feet, the function h(t)=-16t squared +198 gives the height of the object after t seconds. When will the object hit the ground?
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Mathematics
1 year
2021-09-01T14:14:32+00:00
2021-09-01T14:14:32+00:00 1 Answers
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Answer:
The object hits the ground after 3.52 seconds.
Step-by-step explanation:
The height of the object after t seconds is given by the following function:
[tex]h(t) = -16t^2 + 198[/tex]
When will the object hit the ground?
It hits the ground when [tex]h(t) = 0[/tex]. So
[tex]-16t^2 + 198 = 0[/tex]
[tex]16t^2 = 198[/tex]
[tex]t^2 = \frac{198}{16}[/tex]
[tex]t^2 = 12.375[/tex]
[tex]t = \pm \sqrt{12.375}[/tex]
Since time is a positive measure, we only take the positive value
[tex]t = 3.52[/tex]
The object hits the ground after 3.52 seconds.