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If an investment account starts with $3,900, and grows with 2.1% interest, compounded annually, how much is the account worth after 15 years
Question
If an investment account starts with $3,900, and grows with 2.1% interest, compounded annually, how much is the account worth after 15 years?
Round your answer to the nearest dollar.
Do NOT round until you have calculated the final answer.
Answer 5327
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2021-09-04T17:04:30+00:00
2021-09-04T17:04:30+00:00 1 Answers
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Answers ( )
Answer:
$5327
Step-by-step explanation:
Use the formula for calculating compound interest
A(t)=P(1+r/n)^n⋅t,
where A(t) is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded each year, and t is the time (in years). We are given that P=$3,900, r=0.021, n=1, and t=15. Substituting the values into the formula and using a calculator to evaluate, we find
A(t)=P(1+r/n)^n⋅t = $3,900(1+0.0211)^(15)(1) ≈ $5,326.61
So the final answer is $5,327.