If a rectangle has a length of 10 and an area of 50 Units squared what is the perimeter

Question

If a rectangle has a length of 10 and an area of 50 Units squared what is the perimeter

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Tryphena 6 months 2021-07-17T09:39:09+00:00 2 Answers 16 views 0

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    0
    2021-07-17T09:40:38+00:00

    Answer:

    The perimeter is 10+10+5+5, or 30.

    Step-by-step explanation:

    The formula to find area is A=LW. Since the area is 50, we can assume that the width is 5, because 10×5=50. The perimeter is made up of the sides of a rectangle, or L+L+W+W. This is 10+10+5+5.

    0
    2021-07-17T09:41:02+00:00

    Answer: 30

    Step 1: Find width

    Before we can find the perimeter, we must first determine the width. We are told that the length is 10, and the area is 50. To find the width, let’s write an equation. We can do so by remembering that the area is equal to the length and width.

    a= l × w
    50= 10 × w

    Now that we have an equation, we can solve. Let’s do so by isolating w. To do so, divide each side by 10.

    50= 10 × w
    5= w

    Step 2: Find perimeter

    We now know the width. Let’s use our knowledge to find the perimeter. We can begin by writing the formula for the perimeter, and substituting each factor to find out answer. Remember that the perimeter is all of the sides added together.

    p= L+L+w+w
    p= 2L+2w
    p= 2(10)+2(5)
    p= 20+10
    p= 30

    Hope this helps! Comment below for more questions.

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