If a current flowing through a lightbulb is 0.75 ampere and the voltage difference across the lightbulb is 120 volts, how much resistance do

Question

If a current flowing through a lightbulb is 0.75 ampere and the voltage difference across the lightbulb is 120 volts, how much resistance does the light bulb have

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Kim Cúc 6 months 2021-07-15T10:29:33+00:00 1 Answers 30 views 0

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    2021-07-15T10:31:14+00:00

    Answer: 160 \Omega

    Explanation:

    According to Ohm’s law:  

    V=R.I  

    Where:  

    V=120 V is the voltage difference across the light bulb

    R is the resistance of the light bulb   (the value we want to find)

    I=0.75 A is the electric current

    Isolating R:  

    R=\frac{V}{I}

    R=\frac{120 V}{0.75 A}

    Finally:

    R=160 \Omega  This is the resistance of the light bulb

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