If a 20 N force acts on a 10 kg object for 0.5 seconds. If the object starts at rest, what would it’s new p (momentum) and v (velocity) be?

Question

If a 20 N force acts on a 10 kg object for 0.5 seconds. If the object starts at rest, what would it’s new p (momentum) and v (velocity) be?

in progress 0
Orla Orla 4 years 2021-08-02T14:11:57+00:00 1 Answers 10 views 0

Answers ( )

  1. Xavia
    0
    2021-08-02T14:13:13+00:00
    Reply

    Answer:

    p=10\:\text{kgm/s}},\\v_f=1\:\text{m/s}

    Explanation:

    From Newton’s 2nd Law, we have \Sigma F=ma. We can use this to find the acceleration of object after 20 N (force) is applied to the 10 kg object.

    Substituting given values, we have:

    \Sigma F=ma, \\20=10a,\\a=\frac{20}{10}=2\:\mathrm{m/s^2}

    Now that we have acceleration, we can find the final velocity of object (after 0.5 seconds) using the following kinematics equation:

    v_f=v_i+at, where v_f is final velocity, v_i is initial velocity, a is acceleration, and t is time.

    Solving for final velocity:

    v_f=0+2\cdot 0.5,\\v_f=\boxed{1\:\text{m/s}}

    The momentum of an object is given as p=mv. Since we’ve found the final velocity and mass stays constant, we have:

    p=10\cdot 1=\boxed{10\:\text{kgm/s}}

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )