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If 320 J of work is done on a spring with a spring constant of 730 N/m, how far will it stretch? a 0.58 m b0.87 m c0.94m
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Answer:
0.94 m
Explanation:
EE = ½ kx²
320 J = ½ (730 N/m) x²
x = 0.94 m