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if 315mL of 1.25 M iron(ii) sulfate is added to 405mL of.95 M ammonium phosphate, what is the limiting reactant
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Answers ( )
Answer:
FeSO₄ is the Limiting Reactant
Explanation:
3FeSO₄(aq) + 2(NH₄)₃PO₄ (aq) => 3(NH₄)₃PO₄(aq) + Fe₃(PO₄)(s)
315ml(1.25M)FeSO₄ + 405ml(0.95M)(NH₄)₃PO₄
=> 0.315L(1.25M)FeSO₄ + 0.405ml(0.95M)(NH₄)PO₄
=> 0.394mole FeSO₄ + 0.385mole (NH₄)PO₄
Divide by respective coefficient => the smaller value is the Limiting Reactant.
=> 0.394/3 = 0.131 => 0.385/2 = 0.193
Smaller value is associated with FeSO₄
∴the limiting reactant is FeSO₄.
Summery:
1. convert reactant quantities to moles
2. divide reactants by respective coefficients of balanced equation
3. note smaller value after dividing by respective coefficient => Limiting Reactant.