if 2^x > 4^ 15 and x is a positive integer, what is the least possible value of x?

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if 2^x > 4^ 15 and x is a positive integer, what is the least possible value of x?

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Sigridomena 7 months 2021-07-20T20:35:36+00:00 1 Answers 6 views 0

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    2021-07-20T20:37:01+00:00

    Answer:

    x = 31

    Step-by-step explanation:

    2^x > 4^ 15

    Rewrite 4 as 2^2

    2^x > 2^2^ 15

    We know a^b^c = a^(b*c)

    2^x > 2^ (2*15)

    2^x > 2^30

    Since the bases are the same, the exponents must follow the inequality

    x> 30

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