If 12.3 g of Cu is deposited at the cathode of an electrolytic cell after 5.50 h, what was the current used?​

Question

If 12.3 g of Cu is deposited at the cathode of an electrolytic cell after 5.50 h, what was the current used?​

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Thanh Thu 4 years 2021-07-13T12:33:20+00:00 1 Answers 8 views 0

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  1. lethu
    0
    2021-07-13T12:34:39+00:00
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    Answer:

    Current used = 1.90 A

    Explanation:

    The Faraday’s first law of electrolysis states:

    M = ZIt

    where: M is the mass of the element deposited, Z is the electrochemical equivalence of the element, I is the amount of current required and t is the time taken.

    From the given question, M = 12.3 g, t = 5.5 h (19800 s) and Z = 0.0003296 g/C.

    So that,

    12.3 = 0.0003296 x I x 19800

    12.3 = 6.52608 I

    I = \frac{12.3}{6.52608}

     = 1.88475

    I = 1.90 A

    The value of the current used used is 1.90 A

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