I need this now On the planet Xenos, an astronaut observes that a 2.0 m long pendulum has a period of 2.2 s. What is the f

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I need this now

On the planet Xenos, an astronaut observes that a 2.0 m long pendulum has a period of 2.2 s.
What is the free-fall acceleration on Xenos? *

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Thu Hương 6 months 2021-07-21T16:25:53+00:00 1 Answers 0 views 0

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    2021-07-21T16:26:58+00:00

    Answer:

    g=16.31\ m/s^2

    Explanation:

    Given that,

    The length of the pendulum, l = 2 m

    The period of the pendulum, T = 2.2 s

    The formula for the time period of a pendulum is given by :

    T=2\pi \sqrt{\dfrac{l}{g}}

    or

    T^2=4\pi ^2\dfrac{l}{g}\\\\g=\dfrac{4\pi ^2l}{T^2}\\\\g=\dfrac{4\pi ^2\times 2}{(2.2)^2}\\\\g=16.31\ m/s^2

    So, the free fall acceleration is 16.31\ m/s^2.

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