I need some help 3KOH + FeCl3 → Fe(OH)3 + 3KCl How many moles of FeCl3 are needed to completely react with 3.0 g of KOH?

Question

I need some help
3KOH + FeCl3 → Fe(OH)3 + 3KCl
How many moles of FeCl3 are needed to completely react with 3.0 g of KOH?

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Xavia 3 years 2021-07-26T00:13:34+00:00 1 Answers 4 views 0

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  1. Ladonna
    0
    2021-07-26T00:15:05+00:00
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    Answer:

    0.0178

    Explanation:

    because you can work out the amount of moles in KOH using moles = mass/mr.

    The mr of the KOH is 39.1+16+1=56.1 so you do

    \frac{3}{56.1}

    which equals to 0.053475 so u 3SF which is 0.0535moles

    than u uses the molar ratio which is 3 to 1

    so 0.0535÷3=0.0178 which is the moles of FeCl3.

    hope this make sense:)

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