How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

Question

How much volume will 8.8 moles of gas fill at 0.12 atm at 56*C

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RobertKer 5 months 2021-09-02T07:29:32+00:00 1 Answers 0 views 0

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    2021-09-02T07:30:47+00:00

    Answer:

    2000 L

    General Formulas and Concepts:

    Atomic Structure

    • Moles
    • Temperature Conversion: K = °C + 273.15

    Gas Laws

    Ideal Gas Law: PV = nRT

    • P is pressure
    • V is volume (in L)
    • n is number of moles
    • R is gas constant
    • T is temperature (in K)

    Explanation:

    Step 1: Define

    [Given] 8.8 moles gas

    [Given] 0.12 atm

    [Given] 56 °C = 329.15 K

    Step 2: Solve for V

    1. Substitute in variables [Ideal Gas Law Formula]:                                           \displaystyle (0.12 \ atm)V = (8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)
    2. Isolate V:                                                                                                           \displaystyle V = \frac{(8.8 \ mol)(0.0821 \ \frac{L \cdot atm}{mol \cdot K})(329.15 \ K)}{(0.12 \ atm)}
    3. Multiply/Divide [Cancel out units]:                                                                   \displaystyle V = 1981.7 \ L

    Step 3: Check

    Follow sig fig rules and round. We are given 2 sig figs.

    1981.7 L ≈ 2000 L

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