How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?

Question

How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?

in progress 0
Kim Cúc 4 years 2021-08-13T12:50:46+00:00 1 Answers 22 views 0

Answers ( )

  1. huyenthanh
    0
    2021-08-13T12:52:00+00:00
    Reply

    Answer:

    55.9 g KCl.

    Explanation:

    Hello there!

    In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

    m=\frac{mol}{kilograms}

    Thus, solving for the moles of solute, we obtain:

    mol=m*kilograms

    Since the density of water is 1 kg/L, we obtain the following moles:

    mol=0.500mol/kg*1.50kg\\\\mol=0.75mol

    Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

    0.75mol*\frac{74.5513g}{1mol}\\\\55.9g \ KCl

    Regards!

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )