How much (in m) will a spring that has a force constant of 44.5 N/m be stretched by an object with mass 0.490 kg when hung motionless from t

Question

How much (in m) will a spring that has a force constant of 44.5 N/m be stretched by an object with mass 0.490 kg when hung motionless from the spring?

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Tài Đức 4 years 2021-08-18T22:29:19+00:00 1 Answers 6 views 0

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  1. thnahdat
    0
    2021-08-18T22:30:28+00:00
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    Answer:

    0.108 m

    Explanation:

    From Hooke’s law, we have that Force applied to a spring and the corresponding extension is given as:

    F = ke

    where k = spring constant

    We also know that weight (force) is given as:

    F = mg

    where m = mass and g = acceleration due to gravity

    => ke = mg

    => e = mg / k

    Therefore, the extension on the spring is:

    e = (0.49 * 9.80) / 44.5 = 0.108 m

    It will be stretched by 0.108 m

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