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how much force is required to pull a spring 3.0 cm from its equilibrium position if the spring constant is 2.7×10^3 N/m?
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Answer:
I know that T= kx where T is the tension which equaka the force og gravity = mg = 1.37 * 10 = 13.7 x is the elongation of the spring so the length after dangling the object minus the original length.
I hope it helps
plz let me know if it is wrong or right.