how much force is required to pull a spring 3.0 cm from its equilibrium position if the spring constant is 2.7×10^3 N/m?

Question

how much force is required to pull a spring 3.0 cm from

its equilibrium position if the spring constant is 2.7×10^3 N/m?

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Dulcie 3 years 2021-07-27T13:21:17+00:00 1 Answers 126 views 0

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    2021-07-27T13:23:03+00:00

    Answer:

    I know that T= kx where T is the tension which equaka the force og gravity = mg = 1.37 * 10 = 13.7 x is the elongation of the spring so the length after dangling the object minus the original length.

    I hope it helps

    plz let me know if it is wrong or right.

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