How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from the pivot?

Question

How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from the pivot?

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Thành Công 3 days 2021-07-19T23:17:17+00:00 1 Answers 1 views 0

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    2021-07-19T23:18:48+00:00

    Answer:

    Force, F = 622.28 N

    Explanation:

    It is given that,

    Torque, \tau=100\ N-m

    Angle between force and displacement, \theta=40^{\circ}

    Distance, d = 25 cm = 0.25 m

    We need to find the force required to produce the torque. Torque produced by an object is given by :

    \tau=Fd\sin\theta

    F is force required to produce torque

    F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N

    So, applied force is 622.28 N.

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