How much elastic energy is stored in a slingshot that has a spring constant of 300 N/m and is stretched by 0.45m?

Question

How much elastic energy is stored in a slingshot that has a spring constant of 300 N/m and is stretched by 0.45m?

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Nem 2 months 2021-07-25T02:39:18+00:00 1 Answers 1 views 0

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    2021-07-25T02:40:57+00:00

    Answer:

    E = 30.37 J

    Step-by-step explanation:

    Given that,

    The spring constant of the spring, k = 300 N/m

    The spring is stretched by 0.45 m, x = 0.45 m

    We need to find the elastic energy stored in the spring. The formula for the elastic energy is given by :

    E=\dfrac{1}{2}kx^2\\\\=\dfrac{1}{2}\times 300\times (0.45)^2\\\\=30.37\ J

    So, the required elastic energy is equal to 30.37 J.

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