How many solutions does the equation 4y + 7 = 5 + 2 + 4y have? A. One B. Two C. None D. Infinitely many

Question

How many solutions does the equation 4y + 7 = 5 + 2 + 4y have?
A. One
B. Two
C. None
D. Infinitely many

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Khang Minh 6 months 2021-07-26T08:17:30+00:00 2 Answers 9 views 0

Answers ( )

    0
    2021-07-26T08:18:30+00:00

    Answer:

    D. infinitely many

    Step-by-step explanation:

    5+2 = 7 so 4y + 7 = 5 + 2 + 4y just equals 4y + 7=4y + 7 and any value of y is true in that equation.

    0
    2021-07-26T08:19:21+00:00

    Answer:

    D 🙂

    Step-by-step explanation:

    Add 55 and 22.

    4y+7=7+4y4y+7=7+4y

    Move all terms containing yy to the left side of the equation.

    Subtract 4y4y from both sides of the equation.

    4y+7−4y=74y+7-4y=7

    Combine the opposite terms in

    Subtract 4y4y from 4y4y.

    0+7=70+7=7

    Add 00 and 77.

    7=77=7

    Since 7=77=7, the equation will always be true for any value of yy.

    All real numbers

    The result can be shown in multiple forms.

    All real numbers

    Interval Notation:

    (−∞,∞)

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )