How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?

Question

How many moles of silver chloride, produced from 100 g of silver nitrate reacting with barium chloride BaCl2?

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Khang Minh 5 months 2021-08-09T07:00:51+00:00 1 Answers 7 views 0

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    2021-08-09T07:02:01+00:00

    Answer:

    Equation of Reaction

    2AgNO3 + BaCl2 === 2AgCl + Ba(NO3)2

    Molar Mass of AgNO3 = 170g/mol

    Moles of reacting AgNO3 = 100g/170gmol-¹

    =0.588moles of AgNO3

    From the equation of reaction…2moles of AgNO3 reacts to Produce 2Moles of Silver Chloride

    So Their ratio is 2:2.

    This means that 0.588Moles of AgCl Will be produced too.

    ANSWER...0.588MOLES OF AgCl WILL BE PRODUCED.

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