How many moles of KCl are produce when 61.5 g of KClO3 are decomposed?

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How many moles of KCl are produce when 61.5 g of KClO3 are decomposed?

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Gia Bảo 4 years 2021-08-01T16:36:54+00:00 1 Answers 12 views 0

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  1. nguyetanh
    0
    2021-08-01T16:38:23+00:00
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    Answer:

    0.502mol

    Explanation:

    The balanced chemical equation of the reaction described in this question is as follows:

    2KClO3 → 2KCl+ 3O2

    According to the equation above, 2 moles of KClO3 will produce 2 moles of KCl.

    Using mole = mass/molar mass to convert mass of KClO3 to moles

    Molar mass of KClO3 = 39 + 35.5 + 16(3)

    = 39 + 35.5 + 48

    = 122.5g/mol

    mole = 61.5 g ÷ 122.5g/mol

    mole = 0.502mol

    Since 2 moles of KClO3 will decompose to produce 2 moles of KCl.

    0.502 mol of KClO3 will decompose to produce 0.502 × 2/2

    = 0.502mol of KCl.

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